2(q+2)+q^2=q(q+2)+4

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Solution for 2(q+2)+q^2=q(q+2)+4 equation:


Simplifying
2(q + 2) + q2 = q(q + 2) + 4

Reorder the terms:
2(2 + q) + q2 = q(q + 2) + 4
(2 * 2 + q * 2) + q2 = q(q + 2) + 4
(4 + 2q) + q2 = q(q + 2) + 4

Reorder the terms:
4 + 2q + q2 = q(2 + q) + 4
4 + 2q + q2 = (2 * q + q * q) + 4
4 + 2q + q2 = (2q + q2) + 4

Reorder the terms:
4 + 2q + q2 = 4 + 2q + q2

Add '-4' to each side of the equation.
4 + 2q + -4 + q2 = 4 + 2q + -4 + q2

Reorder the terms:
4 + -4 + 2q + q2 = 4 + 2q + -4 + q2

Combine like terms: 4 + -4 = 0
0 + 2q + q2 = 4 + 2q + -4 + q2
2q + q2 = 4 + 2q + -4 + q2

Reorder the terms:
2q + q2 = 4 + -4 + 2q + q2

Combine like terms: 4 + -4 = 0
2q + q2 = 0 + 2q + q2
2q + q2 = 2q + q2

Add '-2q' to each side of the equation.
2q + -2q + q2 = 2q + -2q + q2

Combine like terms: 2q + -2q = 0
0 + q2 = 2q + -2q + q2
q2 = 2q + -2q + q2

Combine like terms: 2q + -2q = 0
q2 = 0 + q2
q2 = q2

Add '-1q2' to each side of the equation.
q2 + -1q2 = q2 + -1q2

Combine like terms: q2 + -1q2 = 0
0 = q2 + -1q2

Combine like terms: q2 + -1q2 = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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